145.二叉树的后序遍历
题目
LeetCode 简单
题目
给定一个二叉树的根节点 root ,返回 它的 后序 遍历 。
示例:
输入:root = [1,null,2,3]
输出:[3,2,1]
题解
方法:递归
递归
O(n) O(n)
ts
function postorderTraversal(root: TreeNode | null): number[] {
let res = []
if (root) {
const postorder = (node: TreeNode) => {
if (node.left) postorder(node.left)
if (node.right) postorder(node.right)
res.push(node.val)
}
postorder(root)
}
return res
}
const tree = new Tree([3, 9, 20, null, null, 15, 7, 14, 13])
console.log('🌰', tree)
console.log('🌰', postorderTraversal(tree.root))
方法:迭代
栈
O(n) O(n)
ts
function postorderTraversalUserStack(root: TreeNode | null): number[] {
let res = []
if (root) {
const stack = [root]
const outputStack = []
while (stack.length) {
console.log('stack', JSON.stringify(stack.map(i => i.val)))
console.log('outputStack', JSON.stringify(outputStack.map(i => i.val)))
const n = stack.pop()
outputStack.push(n)
if (n.left) stack.push(n.left)
if (n.right) stack.push(n.right)
console.log('---')
}
console.log('最后 outputStack', JSON.stringify(outputStack.map(i => i.val)))
while (outputStack.length) {
const n = outputStack.pop()
res.push(n.val)
}
}
return res
}
console.log('🌰', postorderTraversalUserStack(tree.root))